Three students A, B and C can solve 50%, 60% and 70% sums from a book.

1.	Three students A, B and C can solve 50%, 60% and 70% sums from a book. If one sum from that book is given then to solve, then what is the probability that the problem will be solved?
Answer» P(A) = (50/100) = (5/10), P(B) = (60/100) = (6/10) and P(C) = (70/100) = (7/10) A, B, C are INDEPENDENT EVENTS. ∴ P(A ∪ B ∪ C) = 1 – P(A ∪ B ∪ C)' = 1 – P(A') ∙ P(B') ∙ P(C') = 1 – [(5/10)(4/10)(3/10)] = 1 – (6/100) = 0.94 ans

Three students A, B and C can solve 50%, 60% and 70% sums from a book. If one sum from that book is given then to solve, then what is the probability that the problem will be solved?

Answer»

P(A) = (50/100) = (5/10),

P(B) = (60/100) = (6/10) and

P(C) = (70/100) = (7/10)

A, B, C are INDEPENDENT EVENTS. ∴ P(A ∪ B ∪ C) = 1 – P(A ∪ B ∪ C)'

= 1 – P(A') ∙ P(B') ∙ P(C') =

1 – [(5/10)(4/10)(3/10)] =

1 – (6/100) =

0.94 ans

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Three students A, B and C can solve 50%, 60% and 70% sums from a book. If one sum from that book is given then to solve, then what is the probability that the problem will be solved?​

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Three students A, B and C can solve 50%, 60% and 70% sums from a book. If one sum from that book is given then to solve, then what is the probability that the problem will be solved?