1.

Three spherical balls of glass of radii 6,8 and r cm are melted and formed into a single solid sphere with radius 9 cm which will fit perfectly in a cylinder shaped box, what is the volume of the unauthorized/unoccupied part of the box?➣Need answer with step by step explanation.​

Answer»

\large{\mathcal{\underline{\:\:\:\:Given\:\:\:\:}}}

  • \sf{Radius\:of\:the\:sphere\:,r\:=\:<klux>9</klux>\:cm}

{\mathcal{\underline{We\:know\:that,}}}

\begin{gathered}\:\underline{\boxed{\tt{Volume\:of\:sphere\:=\frac{4}{3}πr^3\:}}}\end{gathered}

\begin{gathered}\:\underline{\boxed{\tt{Volume\:of\:cylinder\:=πr^2h\:}}}\end{gathered}

⠀⠀⠀⠀⠀

\sf{\underline{Now,By\:using\:formula}}

\sf{Volume\:of\:the\:given\:sphere\:=\frac{4}{3}×π×9^3}

\sf{So,volume\:of\:the\:given\:sphere\:=3053.63\:cm^3}

  • As the sphere will FIT PERFECTLY in the cylinder shape box.So,the radius of cylinder will be 9 cm.

\sf{Height\:of\:the\:cylinder\:,h\:=2r}

\sf{\leadsto{Height\:of\:the\:cylinder\:,h\:=2×9\:cm}}

\sf{So,height\:of\:the\:cylinder\:,h\:=18\:cm}

⠀⠀⠀⠀⠀

\sf{\underline{By\:using\:formula}}

\sf{Volume\:of\:the\:given\:cylinder\:=π×9^2×18\:cm^3}

\sf{So,volume\:of\:the\:given\:cylinder\:=4580.44\:cm^3}

  • Volume of unauthorized/unoccupied part of the box = (volume of cylinder-volume of sphere)

\leadstoVolume of unauthorized/unoccupied part of the box = (4580.44-3053.63) cm³

\leadstoVolume of unauthorized/unoccupied part of the box = 1526.81 cm³

\begin{gathered}\:\:\:\underline{\boxed{\tt{Hence,the\:volume\:of\:unoccupied\:part\:of\:the\:box\:is\:\bf{1526.81\:cm³}}}}\end{gathered}



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