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Three similar cells, each of emf 2 V and internal resistance rOmega send the same current through an external resistance of 2Omega, when connected in series or in parallel. The strength of the current flowing through the external resistance is |
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Answer» `1 A`  In series, the EFFECTIVE emf of cells = `3epsilon`, effective internal RESISTANCE = 3R where `epsilon` is the emf and r is the internal resistance of each cell. In parallel, the effective emf of cells = `epsilon`, effective internl resistance = `(r )/(3)` As per QUESTION, `I=(3epsilon)/(2+3r)=(epsilon)/(2+(r)/(3))` or `6+r=2+3rorr=2Omega` `therefore I=(3xx2)/(2+3xx2)=(6)/(8)=0.75A` 
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