Saved Bookmarks
| 1. |
Three resistors of 5, 10 and 15 Ωare connected in a parallel and the combination isconnected to a battery of 30V. Find: (i) the current flowing through it (ii) The effective resistance |
|
Answer» Step-by-step explanation: GIVEN= three resistors R1,R2and R3 are connected in parallel potential difference,V = 30 (ii) we know that, 1/R1+1R2+1/R3 = 1/5+1/10+1/15 = 1/R= 6+3+2/30 = 11/30 R = 30/11 (i)USING ohm's law, V = IR 30 = I x 30/11 I = 30 x 11/30 = 330/30 = 11 AMPERE |
|