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Three resistors A,B,C are connected as shown in the figure.Each of them dissipates energy to maximum of 18 W .Find the maximum current that can flow through three resistors.

Answer» AGE across a resistorI = current through the resistorR = value of resistance.Power  DISSIPATED by the resistor is GIVEN by : P =  V²/R = I² R       I² = P / REach resistance dissipates energy = 18 WattsMaximum current through B or C or A is given by : I² = 18 Watts/2 ohms           So I = 3 Amperes maximumSince the resistances B and C are connected in parallel, the current that COMES from the resistance A is divided equally between the resistance B and C.   so current through  B = current through resistance C = 1/2 * current thru ASince, the current passing thru resistor A is max = 3 ampere, then the current through resistor B and resistor C  are 1.5 Amperes maximum.


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