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Three resistances of 2 Omega, 3 Omega and 6 Omega are first connected in series and the equivalent resistance is found to be……… Then the three resistances are connected in parallel Now its equivalent resistance is……… |
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Answer» SOLUTION :`11 OMEGA, 1 Omega` In SERIES `R_s=2+3+6=11 Omega` In parallel `1/R_p=1/2+1/3+1/6=1/1 implies R_p=1 Omega` |
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