Three pipes can fill a tank in 15 hours, 12 hours and 10 hours, respec

1.	Three pipes can fill a tank in 15 hours, 12 hours and 10 hours, respectively. If all the three pipes are opened simultaneously for 3 hours, then what percentage of the tank will remain unfilled?1. 17%2. 50%3. 33%4. 25%
Answer» Correct Answer - Option 4 : 25% Given: Three pipes can fill a tank in 15 hours, 12 hours and 10 hours, respectively. If all the three pipes are opened simultaneously for 3 hours Concept Used: Pipe and cistern Calculation: Three pipes can fill a tank in 15 hours, 12 hours and 10 hours, respectively To find the total capacity take lcm of three Lcm of 15,12 and 10 is 60 Total capacity = 60 unit which is 100% Efficiency of Pipe A = 60/15 = 4 Efficiency of Pipe B = 60/12 = 5 Efficiency of Pipe C = 60/10 = 6 As per the question, All three pipes were opened for 3 hours ⇒ (4 + 5 + 6) × 3 ⇒ 45 unit work done Remaining work ⇒ 60 - 45 = (15/60) × 100 = 25%

Three pipes can fill a tank in 15 hours, 12 hours and 10 hours, respectively. If all the three pipes are opened simultaneously for 3 hours, then what percentage of the tank will remain unfilled?1. 17%2. 50%3. 33%4. 25%

Answer» Correct Answer - Option 4 : 25%

Given:

Three pipes can fill a tank in 15 hours, 12 hours and 10 hours, respectively. If all the three pipes are opened simultaneously for 3 hours

Concept Used:

Pipe and cistern

Calculation:

Three pipes can fill a tank in 15 hours, 12 hours and 10 hours, respectively

To find the total capacity take lcm of three

Lcm of 15,12 and 10 is 60

Total capacity = 60 unit which is 100%

Efficiency of Pipe A = 60/15 = 4

Efficiency of Pipe B = 60/12 = 5

Efficiency of Pipe C = 60/10 = 6

As per the question,

All three pipes were opened for 3 hours

⇒ (4 + 5 + 6) × 3

⇒ 45 unit work done

Remaining work

⇒ 60 - 45 = (15/60) × 100 = 25%

Discussion

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