Saved Bookmarks
| 1. |
Three persons `P_(1), P_(2)`, and `P_(3)` are at three different points A, B and C as shown in the figure. `P_(1)` and `P_(2)` clap at the same time. For `P_(3)` to hear two distinct claps, the minimum distance between `P_(1)` and `P_(2)` should be _______ m. (The velocity of sound in air is `330 ms^(-1)`) A. 33B. 330C. 363D. 660 |
|
Answer» Correct Answer - A Human ear can hear two sounds separately only if they reach the ear after an interval of (1/10) of a second. So, the time taken by the sound from `P_(1)` to `P_(2)` should be greater than `(1//10) s = 0.1 s.` The minimum distance between `P_(1)` and `P_(2)` `= v xx t = 330 xx 0.1 = 33 m.` |
|