Three particles each of mass 100g are placed at the vertices of an equilateral triangle of side length 10cm. Find the moment of inertia of the system about an axis passing through the centroid of the triangle and perpendicular to its plane.

Three particles each of mass 100g are placed at the vertices of an equ

1.	Three particles each of mass 100g are placed at the vertices of an equilateral triangle of side length 10cm. Find the moment of inertia of the system about an axis passing through the centroid of the triangle and perpendicular to its plane.
Answer» Solution :`m=100g=100xx10^(-3)KG`, side `a=10cm=0.1m` Moment of INERTIA `I=3m^(2)` `=3xx100xx10^(-3)((10)/(sqrt(3)xx10^(-2))^(2)=10^(-3)kkgm^(2)`