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Three numbers whose sum is 18 are in AP if 2,4, 11 are added to them respective the resulting numbers are in GP. Find the numbers. |
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Answer» Let the numbers are `a-r, a and a+r`. Then,`a+a-r+a+r = 18=> 3a = 18=> a = 6` We are given if we add 2,4 and 11 to these numbers, it will be in GP.So, `(6+4)/(6-r+2) = (6+r+11)/((6+4)` `=>10/(8-r) = (17+r)/10` `=> (17+r)(8-r) = 100` `=>r^2+9r-136+100 = 0` `=>r^2+9r-36 = 0` `=>(r+12)(r-3) = 0` `r = -12 and r = 3` When `r = -12`, then numbers are, `18, 6, -6`. When `r = 3`, then numbers are `3,6, 9`. |
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