Three numbers are in the ration 3:7:9. If 5 is subtracted from the sec

1.	Three numbers are in the ration 3:7:9. If 5 is subtracted from the second the resulting numbers are in AP. Find the original no .
Answer» Let the three numbers which are in the ratio 3:7:9 be 3x,7x and 9x. Now, on subtracting 5 from the second number, we get the Three numbers as 3x, 7x-5 and 9x Since, these numbers are in AP, therefore, we have 2(7x-5) = 3x+9x 14x-10 = 12x 2x=10 x=5 Hence, the three original numbers are 3x =15, 7x=35 and 9x =45 2nd Method Since, these numbers are in AP, therefore, the common differences between them will be same, we have 7x-5-3x = 9x-7x+5 4x-5 = 2x+5 2x = 10 x = 10/2 = 5 x=5 Hence, the three original numbers are 3x =15, 7x=35 and 9x =45

Three numbers are in the ration 3:7:9. If 5 is subtracted from the second the resulting numbers are in AP. Find the original no .

Answer»

Let the three numbers which are in the ratio 3:7:9 be 3x,7x and 9x.

Now, on subtracting 5 from the second number, we get the

Three numbers as 3x, 7x-5 and 9x

Since, these numbers are in AP, therefore, we have

2(7x-5) = 3x+9x

14x-10 = 12x

2x=10

x=5

Hence, the three original numbers are 3x =15, 7x=35 and 9x =45

2nd Method

Since, these numbers are in AP, therefore, the common differences between them will be same, we have

7x-5-3x = 9x-7x+5

4x-5 = 2x+5

2x = 10

x = 10/2 = 5

x=5

Hence, the three original numbers are 3x =15, 7x=35 and 9x =45

Discussion

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