1.

Three Numbers are in Arithmetic Progression and their sum is 18 and sum oftheir squares is 140. Find the Numbers.

Answer»

let the numbers be (a-d),a,(a+d)sum = a-d +a + a+d = 18 3a=18 a=6so the numbers are (6-d) ,(6) ,(6+d)sum of squares = 36+d²-12d+36+36+d²+12d = 140 108+2d²=140 2d²= 32 d² =16 d=4so the no are 2,6,10



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