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Three moles of B2H6 are completely reacted with methanol. The number of moles of boron containing product formed is__ |
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Answer» Correct answer is 6 B2H6 + 6MeOH → 2B (OMe)3 + 6H2 1 mole of B2H6 reacts with 6 mole of MeOH to give 2 moles of B(OMe)3. 3 mole of B2H6 will react with 18 mole of MeOH to give 6 moles of B(OMe)3 |
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