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Three discs, A, B and C having radii 2m, 4m and6m respectively are coated with carbon black on their outer surfaces. The wavelengths corresponding to maximum intensity are `300nm, 400nm` and `500 nm`, respectively. The power radiated by them are `Q_A, Q_B and Q_C` respectively (a) `Q_A` is maximum (b) `Q_B` is maximum (c) `Q_C` is maximum (d) `Q_A = Q_B = Q_C`A. `Q_(a)` is maximumB. `Q_(b)` is maximumC. `Q_(C )` is maximumD. `Q_(a) = Q_(b) = Q_(c )` |
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Answer» Correct Answer - C (3) `lambda_(1) T_(1) = lambda_(2) T_(2) = lambda_(3) T_(3)` `300 T_(1) = 400 T_(2) = 500 T_(3)` `3 T_(1) = 4 T_(2) = 5 T_(3) = k, k:` constant `Q = sigma A T^(4) = sigma. Pi r^(2) T^(4)` `Q prop r^(2) T^(4)` `Q_(a) : Q_(b) : Q_(c ) = (2)^(2) ((k)/(3))^(4) : (4)^(2) ((k)/(4))^(4) : (6)^(2) ((k)/(5))^(4)` `= (1)/(81) : (1)/(16) : (36)/(25)` `Q_(C ) gt Q_(b) gt Q_(a)` |
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