1.

three cubes whose edges measure 3cm,4cm,and 5cm respectively to form a single cube find its edge. Also find the surface area of new cube.​

Answer»

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\Large{\mathcal{\underline{\underline{Given \ :-}}}}

{\odot{}}Edges of cubes = 3cm , 4cm and 5cm

\Large{\mathcal{\underline{\underline{To \ find \ :-}}}}

{\odot{}} Edge of new cube

{\odot{}} Surface AREA of new cube

\Large{\mathcal{\underline{\underline{Solution \ :-}}}}

{\purple{\star{}}} Since the small cubes are USED to form the big cube.

{\therefore{}} VOLUME of big cube = Sum of volume of small cubes

{\boxed{\sf \ Volume \ of \ cube \ = \  {side}^{3} }}

{\sf{\mapsto  \ Volume \ of \ big \ cube \ = \ {3}^{3}  +  {4}^{3}  +  {5}^{3} }}

{\sf{\mapsto  \ Volume \ of \ big \ cube \ = \ 27+64+125 }}

{\sf{\mapsto  \ Volume \ of \ big \ cube \ = \ 216 {cm}^{3}  }}

{\mathfrack{\Large{Now}}}

{\sf{\leadsto \ Volume \ of \ big \ cube \ = \ 216 {cm}^{3}  }}

{\sf{\leadsto  \  {side}^{3}  \ = \ 216 {cm}^{3}  }}

{\sf{\leadsto  \  side  \ = \   \sqrt[3]{216} }}

{\sf{\leadsto  \  side  \ = \ 6 cm}}

{\bold{\underline{\sf \ Hence \ edge \ of \ cube = 6 cm}}}

{\boxed{\sf \ Surface \ area \ of \ cube = 6 {side}^{2} }}

{\sf{\hookrightarrow \ Surface \ area \ of \ new \ cube = 6 \times 6 \times 6}}

{\bold{\hookrightarrow \sf \ Surface \ area \ of \ new \ cube = 216 {cm}^{2} }}



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