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Three copper wires of length and cross-sectional areas are (L,A)`(2L,(A)/(2)),(L//2,2A)`, resistance isA. minimum in wire of cross-sectional area `(A)/(2)`B. minimum in wire of cross-sectional area AC. minimum in wire of cross-sectional area 2AD. same in all three cases |
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Answer» Correct Answer - C `l_(1)=L,A_(1)=A` `l_(2)=2L, A_(2)=(A)/(2)` `(R_(1))/(R_(2))=(l_(1))/(l_(2))xx(A_(2))/(A_(1)) implies R_(3) lt R_(1) lt R_(2)` |
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