Three coins are tossed simultaneously. Find the probability of getting

1.	Three coins are tossed simultaneously. Find the probability of getting(a) exactly 2 heads (b) at least 1 head(c) no head
Answer» <P>Step-by-step explanation: ${ \huge{ \boxed{ \tt{ \color{blue}{answer}}}}}$ When 3 unbiased COINS are tossed once. And, therefore, N(S) = 8. and, therefore, n(E1) = 1. Therefore, P(getting all heads) = P(E1) = n(E1)/n(S) = 1/8.

Three coins are tossed simultaneously. Find the probability of getting(a) exactly 2 heads (b) at least 1 head(c) no head

Answer»

<P>Step-by-step explanation:

${ \huge{ \boxed{ \tt{ \color{blue}{answer}}}}}$

When 3 unbiased COINS are tossed once. And, therefore, N(S) = 8. and, therefore, n(E1) = 1. Therefore, P(getting all heads) = P(E1) = n(E1)/n(S) = 1/8.

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Three coins are tossed simultaneously. Find the probability of getting(a) exactly 2 heads (b) at least 1 head(c) no head

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