1.

Three capacitors of capacity C are arranged in which manner so that the resulted capacity be 2/3 C?

Answer»

FIRST, CONNECT TWO CAPACITORS IN PARALLEL.

HENCE EQUIVALENCE CAPACITANCE WILL BE 

                    CE=C+C = 2C

CONNECT THE THIRD CAPACITOR IN SERIES

                  1/CT=1/2C+1/C

                   CT=2/3C



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