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Three boys Ravi, John and Asif stand in a straight line as shown in figure. Ravi and Asif fire crackers at the same instant of time. John hears the first sound after 2 s and the second sound after 2.5 s. Determine the distance between Ravi and Asif. The velocity of sound in air is `330 ms^(-1)`. |
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Answer» Let the distance from Ravi to John be `d_(1)`, and the distance from Asif to John be `d_(2)`. `V = d_(1)/t_(1)` Let `t_(1) = 2 s, therefore d_(1) = 2 xx 330 = 660 m` Let `t_(2) = 2.5 s, therefore d_(2) = 2.5 xx 330 = 825 m.` Total distance`= 660 + 825 = 1485 m.` Thus, the distance between Ravi and Asif = `1485 m` |
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