This section contains four questions, each having two matching lists.

1.	This section contains four questions, each having two matching lists. Choices for the correct combination of elements from List – I and List – II are given as options (A), (B), (C) and (D), out of which one is correct. List - IList - IIP.If α=π7 then1cosα+2 cosαcos 2α1.2Q.Ltx→∞[(x−1)(x−2)(x+3)(x+5)(x+10)]15−x=2.3R.∫2−23x2dx1+ex=3.4S.Let f(x)=x3+x2+2x−1.The minimum integral value of x4.8if x satisfies f(f(x)) > f(2x + 1) is
Answer» This section contains four questions, each having two matching lists. Choices for the correct combination of elements from List – I and List – II are given as options (A), (B), (C) and (D), out of which one is correct. $\begin{matrix} List - I & List - II P . & I f α = \frac{π}{7} t h e n \frac{1}{c o s α} + \frac{2 c o s α}{c o s 2 α} & 1. & 2 Q . & L t x \to \infty [(x - 1) (x - 2) (x + 3) (x + 5) (x + 10)]^{\frac{1}{5}} - x = & 2. & 3 R . & \int_{- 2}^{2} \frac{3 x^{2} d x}{1 + e^{x}} = & 3. & 4 S . & Let f(x) = x^{3} + x^{2} + 2 x - 1. The minimum integral value of x & 4. & 8 if x satisfies f(f(x)) > f(2x + 1) is \end{matrix}$

This section contains four questions, each having two matching lists. Choices for the correct combination of elements from List – I and List – II are given as options (A), (B), (C) and (D), out of which one is correct. List - IList - IIP.If α=π7 then1cosα+2 cosαcos 2α1.2Q.Ltx→∞[(x−1)(x−2)(x+3)(x+5)(x+10)]15−x=2.3R.∫2−23x2dx1+ex=3.4S.Let f(x)=x3+x2+2x−1.The minimum integral value of x4.8if x satisfies f(f(x)) > f(2x + 1) is

Answer»

This section contains four questions, each having two matching lists. Choices for the correct combination of elements from List – I and List – II are given as options (A), (B), (C) and (D), out of which one is correct.

$\begin{matrix} List - I & List - II P . & I f α = \frac{π}{7} t h e n \frac{1}{c o s α} + \frac{2 c o s α}{c o s 2 α} & 1. & 2 Q . & L t x \to \infty [(x - 1) (x - 2) (x + 3) (x + 5) (x + 10)]^{\frac{1}{5}} - x = & 2. & 3 R . & \int_{- 2}^{2} \frac{3 x^{2} d x}{1 + e^{x}} = & 3. & 4 S . & Let f(x) = x^{3} + x^{2} + 2 x - 1. The minimum integral value of x & 4. & 8 if x satisfies f(f(x)) > f(2x + 1) is \end{matrix}$

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