1.

This is the 2nd time I'm asking this question... please help me out

Answer»

We have EQUATION for trajectory-------

y = xtan \: <klux>THETA</klux> \: - \frac{1}{2} \frac{gx {}^{2} }{u {}^{2}cos {}^{2} theta}
or
y = xtan \: theta - \frac{x {}^{2} }{2u {}^{2} cos {}^{2}theta \frac{1}{g} }
or
y = xtan \: theta - \frac{x {}^{2} }{2u {}^{2} cos \: theta \: sin \: theta \frac{1}{g} } \frac{sintheta}{costheta}
or
y = xtantheta - \frac{x {}^{2} tantheta}{<klux>RANGE</klux>}
or
y = xtantheta(1 - \frac{x}{range} )

Here...

range =x1 + X2

so putting the values we get.....


y=x1.tan(theta)[1 - x1/(x1 + x2)]

or y= x1.tan theta.[x2/(x1+x2)]

=> y=x1x2/(x1+x2) . tan theta.


that is OPTION (b)


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