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this is an equal to 3 and square minus n is a sum of n term of an ap determine the AP and its 24th term. Plz do this fast |
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Answer» Step-by-step EXPLANATION: GIVEN S
=3N 2 −n Then S n−1
=3[3(n−1)] 2 −(n−1) a n
=S n
−S n−1
⇒a n
=[3n 2 −n]−[3(n−1) 2 −(n−1)] =3[n 2 −(n−1) 2 ]−n+n−1 =3(n 2 −n 2 +2n−1)−1=3(2n−1)−1=6n−4 Then, a
=6×25−4=150−4=146 |
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