This has to do with Ratios of Special Right Triangles. Help!

1.	This has to do with Ratios of Special Right Triangles. Help!
Answer» Answer: This has to do with RATIOS of SPECIAL Right Triangles? The answer is yes. Considering the right triangle GIVEN, it has ratios $x, x\sqrt{3}, 2x$ $2x$ is hypotenuse $x\sqrt{3}$ is opposite to angle 30º $x$ is adjacent to angle 30º Using Pythagorean THEOREM: $(2x)^2=x^2+(x\sqrt{3})^2$ $(2x)^2=x^2+(4)^2\\4x^2=x^2+16\\3x^2=16\\x=\frac{4}{\sqrt{3} } \\x=\frac{4\sqrt{3} }{9}$

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Answer:

This has to do with RATIOS of SPECIAL Right Triangles? The answer is yes.

Considering the right triangle GIVEN, it has ratios $x, x\sqrt{3}, 2x$