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Third term of an AP is 8 and the 17th term is 51/2. The 23rd term |
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Answer» Answer: 3rd term=a+(3-1)d=8 a=8-2d--------------(1) 17TH term=a+(17-1)d=51/2 8-2d+16d=51/2 14d=51/2-8 14d=35/2 d=35/2×(1/14) d=5/4 a=8-2(5/4) =8-5/2=11/2 23rd term=11/2+(23-1)5/4 =11/2+(22)(5/4) =11/2+55/2=66/2=33 |
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