Third law of motion in solve in equation v=u-at

1.	Third law of motion in solve in equation v=u-at
Answer» Answer: $\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}}{\color{pink}{:}}}}}$ $\huge{\bold{\red{⇻}}}$ 3rd Law of Motion:- ⇝s = ut + ½at² $\huge{\bold{\red{⇻}}}$ Derivation of 3rd Law of Motion: LET the DISTANCE be “s”. We KNOW that:- Distance = AVERAGE velocity × Time. Also, Average velocity = (U+v)/2 Therefore, Distance (s) = (u+v)/2 × t Also, from v = u + at we have: s = (u+u+at)/2 × t = (2u+at)/2 × t s = (2ut+at²)/2 = 2ut/2 + at²/2 or s = ut +½ at²✔️ ●▬▬▬▬๑۩๑▬▬▬▬●

Answer»

Answer:

$\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}}{\color{pink}{:}}}}}$

$\huge{\bold{\red{⇻}}}$ 3rd Law of Motion:-

⇝s = ut + ½at²

$\huge{\bold{\red{⇻}}}$ Derivation of 3rd Law of Motion:

LET the DISTANCE be “s”.

Distance = AVERAGE velocity × Time. Also, Average velocity = (U+v)/2

Distance (s) = (u+v)/2 × t

Also,

from v = u + at

s = (u+u+at)/2 × t = (2u+at)/2 × t

s = (2ut+at²)/2 = 2ut/2 + at²/2