There's an arithmetic sequence having 9 terms. the sum of 1st and 9th

1.	There's an arithmetic sequence having 9 terms. the sum of 1st and 9th term is 32(a) what is the 5 th term?
Answer» Step-by-step explanation: LET FIRST term = a, COMMON difference = b, t1 = a , t9 = $a + (9–1) \times b$ = $a + 8b$ , according to condition , $a+a+8b = 24$ …..(1), When we find the SUM of first nine terms , we have first term is a , and last term l = a+8b, number of total terms , n= 9, S = $\frac{n}{2} \times \: {a+l}$ = $\frac{9}{2} \times {a +a+8b}.$ Now PUTTING a+a+8b = 24 from equation (1) n/2{a+l} = 9/2{a +a+8b}. Now putting a+a+8b = 24 from equation (1) S = (9/2)*24 =108 _____________________ Hope it will be Helpful