There is a small air bubble inside a glass sphere (µ = 1.5) of radius

1.	There is a small air bubble inside a glass sphere (µ = 1.5) of radius 10 cm. The bubble is 4 cm below the surface and is viewed normally from outside. The apparent depth of the bubble is
Answer» ANSWER: The bubble will appear 3.03 cm below the surface. Explanation: GIVEN that, Refractive INDEX $\mu_{1}=1.5$ Refractive index $\mu_{2}=1$ Radius = -10 cm The bubble is 4 cm below the surface and is viewed normally from outside. $u= -4 cm$ Using formula of refractive index $\dfrac{\mu_{2}}{v}-\dfrac{\mu_{1}}{u}=\dfrac{\mu_{2}-\mu_{1}}{R}$ $\dfrac{1}{v}-\dfrac{1.5}{-4}=\dfrac{1-1.5}{-10}$ $\dfrac{1}{v}= \dfrac{0.5}{10}-\dfrac{1.5}{4}$ $v= -3.03\ cm$ Hence, The bubble will appear 3.03 cm below the surface.