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There are two identical square metallic plates kept on a rough horizontal floor at `t=0`, plates are given angular velocity `omega` and it is given that plate `1` is rotating about its centre `A` and plate `2` is rotating about one of its centre `O`. If `t_(1)` and `t_(2)` are the time taken by both the plates to come to rest then `(t_(1))/(t_(2))` is (Both are independent cases) A. `(1)/(2)`B. `2`C. `(1)/(4)`D. `4` |
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Answer» `tau alpha mgd` `I.((dw)/(dt)) alpha mgd` and `I=K.md^(2)` Therefore `(dw)/(dt) alpha (1)/(d)`(Angular Acceleration of plate is independent of mass) Now apply superposition principal |
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