There are two class rooms A and B. If 5 students are sent from A to B,

1.	There are two class rooms A and B. If 5 students are sent from A to B, then the numbers ofstudents in each class room is same. If 10 students are sent from B to A, then the numbers ofudents in A is double the number of students in B. Then the number of student in[A] 20[C] 40[B][D]3050Consider the points A (10) B (4.0) and4 Then the trianale ARC in
Answer» Answer of the questions is 20 option b is the correct answer. Let number of students in A class = xLet number of students in B class = y Then,As per given conditionx - 5 = y + 5x - y = 10..........(1) x + 10 = 2(y - 10)x - 2y = - 30......(2) Subtract eq(1) - eq(2)-y + 2y = 10 + 30y = 40 Put value of y in eq(1)x - 40 = 10x = 50 Therefore,Number of students in class A is 50 (D) is correct option x - 5= y+5x-y =10→(1)x+10 =2(y-10)x -2y=-30→(2) solving 1 and 2 we getx=20 hence number of student in A is 20 x - 5= y+5x-y =10→(1)x+10 =2(y-10)x -2y=-30→(2) solving 1 and 2 we gety=40x=50hence number of student in A is 50

There are two class rooms A and B. If 5 students are sent from A to B, then the numbers ofstudents in each class room is same. If 10 students are sent from B to A, then the numbers ofudents in A is double the number of students in B. Then the number of student in[A] 20[C] 40[B][D]3050Consider the points A (10) B (4.0) and4 Then the trianale ARC in

Answer»

Answer of the questions is 20

option b is the correct answer.

Let number of students in A class = xLet number of students in B class = y

Then,As per given conditionx - 5 = y + 5x - y = 10..........(1)

x + 10 = 2(y - 10)x - 2y = - 30......(2)

Subtract eq(1) - eq(2)-y + 2y = 10 + 30y = 40

Put value of y in eq(1)x - 40 = 10x = 50

Therefore,Number of students in class A is 50

(D) is correct option

x - 5= y+5x-y =10→(1)x+10 =2(y-10)x -2y=-30→(2) solving 1 and 2 we getx=20

hence number of student in A is 20

x - 5= y+5x-y =10→(1)x+10 =2(y-10)x -2y=-30→(2) solving 1 and 2 we gety=40x=50hence number of student in A is 50