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There are 6 white and 4 black balls in a bag. If four are drawn successively (and not replaced),find the probability that they are alternately of different colour. |
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Answer» SOLUTION :There are 6 white and 4 black balls in a bag. Four balls are DRAWN without replacement. Let W and B denotes the white and black ball. There are TWO mutually exclusive cases WBWB and BWBW. `therefore P(WBWB)=6/10xx4/9xx5/8xx3/7=1/14` P(BWBW)=`4/10xx6/9xx3/8xx5/7xx=1/14` `therefore` Probability that they are ALTERNATELY of different colour`=1/14+1/14=2/14=1/7` |
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