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There are 5 boys and 3 girls. In how many ways can they stand in a row so that no two girls are together?(a) 36000 (b) 25600 (c) 14400 (d) 15600 |
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Answer» (c) 144000 First of all we arrange the 5 boys in 5 ! ways. Then we arrange the 3 girls in the remaining 6 places between the 5 boys and on the extreme in 6P3 ways. × B × B × B × B × B × ∴ Required number of ways = 5 ! × 6P3 = 120 × 6 × 5 × 4 = 144000 |
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