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There are 3 copies each of 4 different books. Find the number of ways of arranging them on a shelf. |
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Answer» Total number of books = 3 × 4 = 12 Each of the 4 different titles has 3 copies each ∴ Required number of ways of arranging them on a shelf = \(\frac{12!}{3!3!3!3}\) = \(\frac{12!}{(3!)^4}\) = 369600. |
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