1.

there are 10 resistance each of value q/4ohm.what are the maximum and the minimum resistance which can be obtained by their combination?

Answer»

ANSWER
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Maximum Resistance is obtained in Series Circuit.

Max R = 1/4 + 1/4 + 1/4 ....... ( 10 TIMES )

Max R = 10 × 1/4 = 5/2

= 2.5 ohm

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Minimum resistance can be obtained by Parallel Circuit.

Minimum R = 1/R = 4 + 4 + 4 ..... ( 10 Times )

1/R = 40

=> R = 1/40

=> 0.025 ohm
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HOPE IT HELPS :):):):)



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