Therate constant for the decomposition of hydrocarbons is 2.418 ×10� – InterviewSolution

1.	Therate constant for the decomposition of hydrocarbons is 2.418 ×10−5s−1at 546 K. If the energy of activation is 179.9 kJ/mol, what will bethe value of pre-exponential factor.
Answer» The rate constant for the decomposition of hydrocarbons is 2.418 × 10⁻⁵s⁻¹ at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of pre-exponential factor.

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