1.

The zeros of the polynomial x2-2x -8 are(A) -4, 2(B) 4, 2(C) -4, -2(D) 4, -2

Answer»

Answer: (D) 4, -2

We have,
f(x) = x2-2x -8
Now, put f(x) = 0
x2-2x -8 = 0
x2- 4x + 2x -8 = 0
x(x - 4) + 2(x - 4) = 0

(x - 4) (x + 2) = 0
x - 4 = 0 or x + 2 = 0
x = 4 or x = -2
So, the zeros of given polynomial are 4 and -2.



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