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The zeros of the polynomial m^3 -3m^2+m+1 are a-b , a , a+b , find a and b |
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Answer» Step-by-step EXPLANATION: The given polynomial is p(m)= m³-3m²+m+1. So sum of the zeroes=a-b+a+a+b=-(-3)/1=3 => 3a=3 => a=3/3 => a=1 (a-b)a+a(a+b)+(a-b)(a+b)=1 => a²-ab+a²+ab+a²-b²=1 => 3a²-b²=1 =>1×3-b²=1 => b²=3-1=2 => b=±√2 So the value of a=1 and b=±√2.(answer) |
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