The Young’s modulus for steel is much more than that for rubber. For

1.	The Young’s modulus for steel is much more than that for rubber. For the same longitudinal strain, which one will have greater tensile stress?
Answer» Young’s Modulus, Y = \(\frac{Stress}{Longitudinal\, Strain}\) Y ∝ stress (for same longitudinal strain) ∴ \(\frac{Y_{steel}}{Y_{rubber}}\) = \(\frac{stress_{steel}}{stress_{rubber}}\) (A) (Given : Y_steel > Y_rubber), ∴ \(\frac{Y_{steel}}{Y_{rubber}}\) > 1 From eqⁿ \(\frac{stress_{steel}}{stress_{rubber}}\) > 1 or stress_steel > stress_rubber

The Young’s modulus for steel is much more than that for rubber. For the same longitudinal strain, which one will have greater tensile stress?

Answer»

Young’s Modulus,

Y = \(\frac{Stress}{Longitudinal\, Strain}\)

Y ∝ stress (for same longitudinal strain)

∴ \(\frac{Y_{steel}}{Y_{rubber}}\) = \(\frac{stress_{steel}}{stress_{rubber}}\) (A)

(Given : Y_steel > Y_rubber),

∴ \(\frac{Y_{steel}}{Y_{rubber}}\) > 1

From eqⁿ \(\frac{stress_{steel}}{stress_{rubber}}\) > 1 or stress_steel > stress_rubber