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the work done per unit volume to stretch the length of area of cross section 2mm^2 by 2% will be (Y=8*10^10N/m^2 |
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Answer» al WORK done in stretching a material per UNIT volume by 2% LENGTH will be 16 MJ/m³Explanation : Given, young's modulus, Y = 8 x 10¹⁰ N/m²percentage CHANGE in length, ΔL/L = 2% = 2/100we KNOW that the total work done in stretching a material is given by,U = 1/2 x Y x (ΔL/L)² x Vhence work done per unit volume= U/V = 1/2 x Y x (ΔL/L)²= 1/2 x 8 x 10¹⁰ x (2/100)²= 16 x 10⁶ joules/m³= 16 MJ/m³Hence the total work done in stretching a material per unit volume by 2% length will be 16 MJ/m³ |
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