1.

The work done in time t on a body of mass m which is accelerated from rest to a speed v in time t_1 as a function of time t is given by

Answer»

`1/2 m (v)/(t_1) t^2`
`m v/(t_1)t^2`
`1/2 ((MV)/(t_1))^(2) t^2`
`1/2 m (v^2)/(t_1^2) t^2`

Solution :As `v =u + at = 0 + at_1 "" ( :. u = 0)`
`:. A = (v)/(t_1) "" ….(i)`
Force, `F = ma = (mv)/(t_1) `
DISTANCE travelled by the body in time t is
`s = UT + 1/2 at^2 = 0 + 1/2 (vt^2)/(t_1) = (vt^2)/(2t_1) "(Using (i))"`
`:. W = F xx s = (mv)/(t_1) (vt^2)/(2t_1) = 1/2 (mv^2 t^2)/(t_1^2)`


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