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The work done in time t on a body of mass m which is accelerated from rest to a speed v in time t_1 as a function of time t is given by |
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Answer» `1/2 m (v)/(t_1) t^2` `:. A = (v)/(t_1) "" ….(i)` Force, `F = ma = (mv)/(t_1) ` DISTANCE travelled by the body in time t is `s = UT + 1/2 at^2 = 0 + 1/2 (vt^2)/(t_1) = (vt^2)/(2t_1) "(Using (i))"` `:. W = F xx s = (mv)/(t_1) (vt^2)/(2t_1) = 1/2 (mv^2 t^2)/(t_1^2)` |
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