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The work done in increasing the size of a soap film from `10cmxx6cm` to `10cmxx11cm` is `3xx10^-4` Joule. The surface tension of the film isA. `3.0xx10^(-2)N//m`B. `6.0xx10^(-2)N//m`C. `1.5xx10^(-2)N//m`D. `11.0xx10^(-2)N//m` |
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Answer» Correct Answer - A The work ………….. `(10xx11-10xx6)xx10^(-4)xx2T=Delta w` `50xx10^(-4)xx2T = 3xx10^(-4)` `implies T = (3)/(100) = 3xx10^(-2)N//m` |
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