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The work done in bringing a charge of 60 Columbus is 180 Joule calculate the potential So Developed |
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Answer» Potential DIFFERENCE between TWO points ΔV=60 VoltsMagnitude of CHARGE q=3×10 −5 CoulombWork DONE W=qΔV⟹ W=3×10 −5 ×60=1.8×10 −3 JOULES |
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