The work done by the system in a cyclic process involving one mole of

1.	The work done by the system in a cyclic process involving one mole of an ideal monoatomic gas is-50KJ/cycle.the heat absorbed by the system per cycle is
Answer» ANSWER: -50kJ/cycle Explanation: Since it is a CYCLIC process, there is no net change in INTERNAL energy, i.e initial and final internal energies are equal. Applying FIRST law of thermodynamics, which, mathematically is ΔU = Q - W Since its a cyclic process, ΔU = 0 Therefore, Q = W Hence, heat absorbed is -50kJ

The work done by the system in a cyclic process involving one mole of an ideal monoatomic gas is-50KJ/cycle.the heat absorbed by the system per cycle is

Answer»

-50kJ/cycle

Explanation:

Since it is a CYCLIC process, there is no net change in INTERNAL energy, i.e initial and final internal energies are equal.

Applying FIRST law of thermodynamics, which, mathematically is

ΔU = Q - W

Since its a cyclic process, ΔU = 0

Therefore,

Q = W

Hence, heat absorbed is -50kJ