The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is

The work done by a force acting on a body is as shown in the graph. Th

1.	The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is
Answer» 225 J 200 J 400 J. 175 J Solution : Work done W = AREA under F - S graph = area of trapezium ABCD = area of trapezium CEFD `=1/2 xx (10 + 15) xx 10 + 1/2 xx (10+ 20) xx 5 = 125 + 75= 200 J`