Saved Bookmarks
| 1. |
The windshield of a truck is inclined at 37^(@) to the horizontal. The truck is moving horizontally with a constant acceleration of a = 5 m//s^(2). At the instant the velocity of the truck is v_(0) = 0.77 m//s, an insect jumps from point A on the windshield, with a velocity u = 2.64 m//s (relative to ground) in vertically upward direction. It falls back at point B on the windshield. Calculate distance AB. Assume that the insect moves freely under gravity and g = 10 m//s^(2). |
|
Answer» |
|