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The weight of pure NaOH required to prepare 250 mL of 0.1 N solution is :A. 4 gB. 2 gC. 1 gD. 5 g |
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Answer» Correct Answer - C `("0.1 Equiv. L"^(-1))=("Mass of NaOH")/(("40 g equiv")^(-1)xx("0.2 5L"))` Mass of `NaOH = 0.1 xx 40 xx 0.25 =1g`. |
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