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The weight of one atom of uraium is 238 amuthe actual weight is |
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Answer» C3H7OH - Molecular mass = 6072.5 g is 72.5/60 = 1.208 moles1 MOLE of C3H7OH contains 3N ATOMS ( N= 6.023 x 10^23) of C1.208 MOLES contains 1.208 x 3N atoms = = 3.624N atoms of C= 2.183 x 10^24 atoms of CSimilarlyno.of O atoms = 1.208N atoms = 7.276 x 10^23 atoms of OREAD more on Brainly.in - brainly.in/question/4870175#readmore |
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