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The weight of a pure sample of a KCL O3 to be decomposer in order to get 0.96 o2 |
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Answer» ➡️ 2KCL + 3O2So, 2×122.5 GM KCLO3 = 3×32 gm O2So, X gm of it = 0.96 O2Hence, X = 2×122.5×0.96/3×32= 2.45 gm KClO3. |
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