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The wavelength of the first line of Lyman series is lamdba for hydrogen atom. Find out the wavelength of first line of Pfund series. |
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Answer» Solution :If `lambda` is the wavelength of first line in Lyman series then `(1)/(lambda)=R[(1)/(1^(2))-(1)/(2^(2))]=R[(1)/(1)-(1)/(4)]` `(1)/(lambda)=(3R)/(4) ....(1)` `RARR` is the wavelength of first line in Pfund series then, `(1)/(lambda.)=R[(1)/(5^(2))-(1)/(6^(2))]=R[(1)/(25)-(1)/(36)]` `(1)/(lambda.)= (11F)/(900)...(2)` `rArr` Taking ratio of equation(1) and (2) `(lambda.)/(lambda)=(3R)/(4)xx(900)/(11R)=(2700)/(44)` `lambda.=61.36 lambda` |
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