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The wavelength of light emitted from second orbit to first orbits in a hydrogen atom isA. `1.215 xx 10^(-7)m`B. `1.215 xx 10^(-5) m`C. `1.215 xx 10^(-4) m`D. `1.215 xx 10^(-3) m` |
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Answer» Correct Answer - A Energy radiated `E = 10.2 eV = 10.2 xx 1.6 xx 10^(-19) J` `rArr E = (hc)/(lambda) rArr = 1.215 xx 10^(-7) m` |
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