Saved Bookmarks
| 1. |
The wavelength of a sound note is 1 m in air and 2.5 m in a liquid. Find the speed of sound in the liquid, if the speed of the sound in air is 330 m/s. |
|
Answer» Given: λa = 1 m, λl = 2.5 m, va = 330 m/s, To find: Speed of sound (vl) Formula: v = nλ Calculation: From formula, Since the frequency n remains the same, va = nλa and vl = nλl ∴ \(\frac{v_l}{v_a}=\frac{λ_l}{λ_a}\) ∴ vl = va \(\frac{λ_l}{λ_a}\) = 330 × \(\frac{2.5}{1}\) = 825 m/s |
|